4y/(2y^-1/5)

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Solution for 4y/(2y^-1/5) equation: 


D( y )

y = 0

(2*y^-1)/5 = 0

y = 0

y = 0

(2*y^-1)/5 = 0

(2*y^-1)/5 = 0

2/5*y^-1 = 0 // : 2/5

y^-1 = 0

y należy do O

y in (-oo:0) U (0:+oo)

(4*y)/((2*y^-1)/5) = 0

10*y^2 = 0 // : 10

y^2 = 0

y = 0

y in { 0} 

y belongs to the empty set

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